RE: [ns] About pareto.cc

["Timothy.Bauge" <Tim.Bauge@rrl.co.uk>]

>> Random::pareto(scale,shape) returns  scale / (u ^ (1 / 
>shape)) where u is
>a
>> uniformly distributed random variable (see rng.h). So 
>dividing scale by
>> interval_ is identical to dividing the random value by 
>interval_. It makes
>> no difference. Or am I misunderstanding what you're saying ?
>
>    It's me who was wrong to think that time resolution was spoiled.
>But I still don't get what pareto really does. While calculating p1_,
>both the avg and shape are taken into consideration. After setting
>p1_ to burstlen_*(shape_ - 1.0)/shape_ and generating a pareto rv,
>its mean is burstlen_, and there's a pursuing rounding-off. What I
>think reasonable is setting p1_ to ontime_*(shape_ - 1.0)/shape_,
>generating a rv, rem_=rv/interval_ ,and no rounding-off.
>Are they basically the same? And that's what confuses me.

You have to round off, as rem_ is required to be an integer (a number of
packets, with a fixed packet size).


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